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TECHNOLOGY
OF DIFFERENTIAL BRIDGE SYSTEMS
DIFFERENTIAL
MEASUREMENTS
In an
eddy current differential system, the two coils in the inductive
bridge are housed in two separate sensors. Rather than one
active coil and one reference coil, both sensors contain active
coils as in figure 2. These two sensors are usually placed
on opposite sides of a target or opposite sides of a target
pivot point, as in figure 1.
THEORY
OF OPERATION
As the
target moves closer to one sensor, it moves away from the
other. Therefore as the impedance in one leg of the inductive
bridge increases, the other decreases. This push-pull effect
amplifies the linear output-per-displacement and eliminates
the need for summation amplifiers that add noise and drift.
As a result, differential systems provide greater resolution
and thermal stability than single-ended systems.
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![[Differential target configurations]](images/DIT-5200targetconfig.gif)
Figure
1: Differential target configurations.
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![[Differential system block diagram]](images/DIT-5200blockdiag.gif)
Figure 2:
Differential system block diagram.
CALCULATING
EFFECTIVE RESOLUTION IN YOUR APPLICATION
Equivalent
RMS input noise: A figure of merit used to quantify the noise
contributed by a system component. It incorporates into a single
value, several factors that influence a noise specification such
as signal-to-noise ratio, noise floor, and system bandwidth. Given
a measuring system's sensitivity/scale factor and the level of "white"
noise in the system, equivalent RMS input noise can be expressed
using actual measurement units.
Effective
resolution: An application dependent value determined by multiplying
the equivalent RMS input noise specification by the square root
of the measurement bandwidth.
Example:
A 15N sensor monitoring a reciprocating target moving ±10
mils (FR) filtered externally to a 15KHz bandwidth.
1. Calculate
a value for equivalent RMS input noise. From the equivalent
RMS input noise table, use the value of equivalent RMS input noise
for a 15N sensor calibrated over a ±10 mil range. Multiply
this by the full range of the calibration. Divide by 100. The noise
value is a percent of full range.
(0.00007%
X 0.020 inches) / 100 = 1.4 x 10-8 inches
or 0.014 µinches
2. Calculate
effective resolution. From step 1, take the equivalent RMS input
noise and multiply by the square root of the measurement bandwidth
in Hz.
0.014 µinches
per root 15000 = 1.714 µinches
3. Approximate
peak-to-peak resolution. From step 2, take the effective resolution
and multiply by 6.6.
1.714 µinches
X 6.6 = 11.312 µinches
EQUIVALENT
RMS INPUT NOISE
|
Range
± mils
|
Range
± mm
|
Sensor
|
%
Full Range
at Full Range
|
%
Full Range
at Null
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| 10 |
0.25 |
15N |
0.00007% |
0.00002% |
| 10 |
0.25 |
20N |
0.00012% |
0.00004% |
| 20 |
0.51 |
15N |
0.00004% |
0.00002% |
| 20 |
0.51 |
20N |
0.00007% |
0.00002% |
| 35 |
0.89 |
15N |
0.00004% |
0.00002% |
| 50 |
1.27 |
20N |
0.00004% |
0.00002% |
| 75 |
1.91 |
20N |
0.00002% |
0.00002% |
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